What are the solutions to the equation -x^3-x^2+5x-3=0 ?

The solutions to the equation -x^3-x^2+5x-3=0 are x=1,x=-3

Find the zeros of -x^3-x^2+5x-3=0

The zeros of -x^3-x^2+5x-3=0 are x=1,x=-3

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- x^{3} - x^{2} + 5 x - 3 = 0

x = 1, x = - 3

Solution steps

- x^{3} - x^{2} + 5 x - 3 = 0

Factor

- x^{3} - x^{2} + 5 x - 3 : - (x - 1)^{2} (x + 3)

- (x - 1)^{2} (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 1, x = - 3

x^{3} = 81 x

2 x^{3} = - 6 x^{2} + x + 3

x^{3} - 5 x = 15 x^{2}

6 x^{4} - 25 x^{3} + 12 x^{2} + 25 x + 6 = 0

- x^{3} + 3 x^{2} = 0

What are the solutions to the equation -x^3-x^2+5x-3=0 ?
The solutions to the equation -x^3-x^2+5x-3=0 are x=1,x=-3
Find the zeros of -x^3-x^2+5x-3=0
The zeros of -x^3-x^2+5x-3=0 are x=1,x=-3