What are the solutions to the equation x^3-5x=15x^2 ?

The solutions to the equation x^3-5x=15x^2 are x=0,x=(15+7sqrt(5))/2 ,x=(15-7sqrt(5))/2

Find the zeros of x^3-5x=15x^2

The zeros of x^3-5x=15x^2 are x=0,x=(15+7sqrt(5))/2 ,x=(15-7sqrt(5))/2

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x^{3} - 5 x = 15 x^{2}

x = 0, x = \frac{15 + 7 5}{2}, x = \frac{15 - 7 5}{2}

Decimal Notation

x = 0, x = 15.32623 \dots, x = - 0.32623 \dots

Solution steps

x^{3} - 5 x = 15 x^{2}

Move

15 x^{2}

to the left side

x^{3} - 5 x - 15 x^{2} = 0

Factor

x^{3} - 5 x - 15 x^{2} : x (x^{2} - 15 x - 5)

x (x^{2} - 15 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} - 15 x - 5 = 0

Solve

x^{2} - 15 x - 5 = 0 : x = \frac{15 + 7 5}{2}, x = \frac{15 - 7 5}{2}

The solutions are

x = 0, x = \frac{15 + 7 5}{2}, x = \frac{15 - 7 5}{2}

6 x^{4} - 25 x^{3} + 12 x^{2} + 25 x + 6 = 0

- x^{3} + 3 x^{2} = 0

x^{7} - 1 = 0

x^{5} = 9 x^{3}

(y - 2)^{4} = 0

What are the solutions to the equation x^3-5x=15x^2 ?
The solutions to the equation x^3-5x=15x^2 are x=0,x=(15+7sqrt(5))/2 ,x=(15-7sqrt(5))/2
Find the zeros of x^3-5x=15x^2
The zeros of x^3-5x=15x^2 are x=0,x=(15+7sqrt(5))/2 ,x=(15-7sqrt(5))/2