What are the solutions to the equation 3x^3-5x^2+3x-5=0 ?

The solutions to the equation 3x^3-5x^2+3x-5=0 are x= 5/3 ,x=i,x=-i

Find the zeros of 3x^3-5x^2+3x-5=0

The zeros of 3x^3-5x^2+3x-5=0 are x= 5/3 ,x=i,x=-i

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3 x^{3} - 5 x^{2} + 3 x - 5 = 0

x = \frac{5}{3}, x = i, x = - i

Solution steps

3 x^{3} - 5 x^{2} + 3 x - 5 = 0

Factor

3 x^{3} - 5 x^{2} + 3 x - 5 : (3 x - 5) (x^{2} + 1)

(3 x - 5) (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 5 = 0 or x^{2} + 1 = 0

Solve

3 x - 5 = 0 : x = \frac{5}{3}

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = \frac{5}{3}, x = i, x = - i

x^{4} + 41 x^{2} + 400 = 0

(x - 2)^{3} = 25 (x - 2)

x^{3} + 3 x^{2} - 2 x - 6 = 0

- x^{3} + 12 x^{2} - 21 x - 98 = 0

x^{3} - x^{2} = 4

What are the solutions to the equation 3x^3-5x^2+3x-5=0 ?
The solutions to the equation 3x^3-5x^2+3x-5=0 are x= 5/3 ,x=i,x=-i
Find the zeros of 3x^3-5x^2+3x-5=0
The zeros of 3x^3-5x^2+3x-5=0 are x= 5/3 ,x=i,x=-i