What are the solutions to the equation x^4+13x^3+42x^2=0 ?

The solutions to the equation x^4+13x^3+42x^2=0 are x=0,x=-6,x=-7

Find the zeros of x^4+13x^3+42x^2=0

The zeros of x^4+13x^3+42x^2=0 are x=0,x=-6,x=-7

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x^{4} + 13 x^{3} + 42 x^{2} = 0

x = 0, x = - 6, x = - 7

Solution steps

x^{4} + 13 x^{3} + 42 x^{2} = 0

Factor

x^{4} + 13 x^{3} + 42 x^{2} : x^{2} (x + 6) (x + 7)

x^{2} (x + 6) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 6 = 0 or x + 7 = 0

Solve

x + 6 = 0 : x = - 6

Solve

x + 7 = 0 : x = - 7

The solutions are

x = 0, x = - 6, x = - 7

x^{3} + 7 x^{2} - 5 x - 35 = 0

x, y^{2} = C x^{3} + 1

h^{4} + 9 = 10 h^{2}

- 3 (36 x^{2} - 25) (x^{2} + 1) = 0

- 2 (x + 8) (25 x^{2} - 49) = 0

What are the solutions to the equation x^4+13x^3+42x^2=0 ?
The solutions to the equation x^4+13x^3+42x^2=0 are x=0,x=-6,x=-7
Find the zeros of x^4+13x^3+42x^2=0
The zeros of x^4+13x^3+42x^2=0 are x=0,x=-6,x=-7