What are the solutions to the equation -x(x+1)(x-7)=0 ?

The solutions to the equation -x(x+1)(x-7)=0 are x=0,x=-1,x=7

Find the zeros of -x(x+1)(x-7)=0

The zeros of -x(x+1)(x-7)=0 are x=0,x=-1,x=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x (x + 1) (x - 7) = 0

x = 0, x = - 1, x = 7

Solution steps

- x (x + 1) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x - 7 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 7 = 0 : x = 7

The solutions are

x = 0, x = - 1, x = 7

(x + 3 a) (2 x^{2} - 11 x + 12) = 0

x^{3} + x^{2} - 4 x + 4 = 0

2 x^{3} - 2 x - 5 = 0

12 x^{4} = 3 x^{2}

8 x^{3} = 27

What are the solutions to the equation -x(x+1)(x-7)=0 ?
The solutions to the equation -x(x+1)(x-7)=0 are x=0,x=-1,x=7
Find the zeros of -x(x+1)(x-7)=0
The zeros of -x(x+1)(x-7)=0 are x=0,x=-1,x=7