What are the solutions to the equation x^3-5x^2+9x-5=0 ?

The solutions to the equation x^3-5x^2+9x-5=0 are x=1,x=2+i,x=2-i

Find the zeros of x^3-5x^2+9x-5=0

The zeros of x^3-5x^2+9x-5=0 are x=1,x=2+i,x=2-i

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x^{3} - 5 x^{2} + 9 x - 5 = 0

x = 1, x = 2 + i, x = 2 - i

Solution steps

x^{3} - 5 x^{2} + 9 x - 5 = 0

Factor

x^{3} - 5 x^{2} + 9 x - 5 : (x - 1) (x^{2} - 4 x + 5)

(x - 1) (x^{2} - 4 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} - 4 x + 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} - 4 x + 5 = 0 : x = 2 + i, x = 2 - i

The solutions are

x = 1, x = 2 + i, x = 2 - i

- x^{3} + 7 x^{2} - 16 x + 12 = 0

y^{3} = - 1

y^{3} = - 8

x^{3} - x^{2} - 2 = 3

x^{3} - 3 x - 2.2 = 0

What are the solutions to the equation x^3-5x^2+9x-5=0 ?
The solutions to the equation x^3-5x^2+9x-5=0 are x=1,x=2+i,x=2-i
Find the zeros of x^3-5x^2+9x-5=0
The zeros of x^3-5x^2+9x-5=0 are x=1,x=2+i,x=2-i