What are the solutions to the equation -x^3+7x^2-16x+12=0 ?

The solutions to the equation -x^3+7x^2-16x+12=0 are x=2,x=3

Find the zeros of -x^3+7x^2-16x+12=0

The zeros of -x^3+7x^2-16x+12=0 are x=2,x=3

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- x^{3} + 7 x^{2} - 16 x + 12 = 0

x = 2, x = 3

Solution steps

- x^{3} + 7 x^{2} - 16 x + 12 = 0

Factor

- x^{3} + 7 x^{2} - 16 x + 12 : - (x - 2)^{2} (x - 3)

- (x - 2)^{2} (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 3 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 3 = 0 : x = 3

The solutions are

x = 2, x = 3

y^{3} = - 1

y^{3} = - 8

x^{3} - x^{2} - 2 = 3

x^{3} - 3 x - 2.2 = 0

x^{3} - 4 x^{2} - 10 x + 40 = 0

What are the solutions to the equation -x^3+7x^2-16x+12=0 ?
The solutions to the equation -x^3+7x^2-16x+12=0 are x=2,x=3
Find the zeros of -x^3+7x^2-16x+12=0
The zeros of -x^3+7x^2-16x+12=0 are x=2,x=3