What are the solutions to the equation 2x^3-24x^2+64x=0 ?

The solutions to the equation 2x^3-24x^2+64x=0 are x=0,x=4,x=8

Find the zeros of 2x^3-24x^2+64x=0

The zeros of 2x^3-24x^2+64x=0 are x=0,x=4,x=8

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2 x^{3} - 24 x^{2} + 64 x = 0

x = 0, x = 4, x = 8

Solution steps

2 x^{3} - 24 x^{2} + 64 x = 0

Factor

2 x^{3} - 24 x^{2} + 64 x : 2 x (x - 4) (x - 8)

2 x (x - 4) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 4 = 0 or x - 8 = 0

Solve

x - 4 = 0 : x = 4

Solve

x - 8 = 0 : x = 8

The solutions are

x = 0, x = 4, x = 8

x^{3} + 4 x^{2} + 8 x + 10 = 0

x^{4} - 20 x^{2} + 99 = 0

3 x (8 x - 9) (x^{2} + 64) = 0

0 = x^{3} - x^{2} - 5 x + 5

5^{2} + 10 = 7 x^{5}

What are the solutions to the equation 2x^3-24x^2+64x=0 ?
The solutions to the equation 2x^3-24x^2+64x=0 are x=0,x=4,x=8
Find the zeros of 2x^3-24x^2+64x=0
The zeros of 2x^3-24x^2+64x=0 are x=0,x=4,x=8