What are the solutions to the equation 3x(8x-9)(x^2+64)=0 ?

The solutions to the equation 3x(8x-9)(x^2+64)=0 are x=0,x= 9/8 ,x=8i,x=-8i

Find the zeros of 3x(8x-9)(x^2+64)=0

The zeros of 3x(8x-9)(x^2+64)=0 are x=0,x= 9/8 ,x=8i,x=-8i

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3 x (8 x - 9) (x^{2} + 64) = 0

x = 0, x = \frac{9}{8}, x = 8 i, x = - 8 i

Solution steps

3 x (8 x - 9) (x^{2} + 64) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 8 x - 9 = 0 or x^{2} + 64 = 0

Solve

8 x - 9 = 0 : x = \frac{9}{8}

Solve

x^{2} + 64 = 0 : x = 8 i, x = - 8 i

The solutions are

x = 0, x = \frac{9}{8}, x = 8 i, x = - 8 i

0 = x^{3} - x^{2} - 5 x + 5

5^{2} + 10 = 7 x^{5}

3 x^{3} + 8 x^{2} - 3 = 0

x (x - 3)^{2} - 4 (x - 3)^{3} = 0

(x + 5)^{3} = - 27

What are the solutions to the equation 3x(8x-9)(x^2+64)=0 ?
The solutions to the equation 3x(8x-9)(x^2+64)=0 are x=0,x= 9/8 ,x=8i,x=-8i
Find the zeros of 3x(8x-9)(x^2+64)=0
The zeros of 3x(8x-9)(x^2+64)=0 are x=0,x= 9/8 ,x=8i,x=-8i