What are the solutions to the equation 5^2+10=7x^5 ?

The solutions to the equation 5^2+10=7x^5 are x=\sqrt[5]{5}

Find the zeros of 5^2+10=7x^5

The zeros of 5^2+10=7x^5 are x=\sqrt[5]{5}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5^{2} + 10 = 7 x^{5}

Decimal Notation

x = 1.37972 \dots

Solution steps

5^{2} + 10 = 7 x^{5}

Switch sides

7 x^{5} = 5^{2} + 10

5^{2} = 25

7 x^{5} = 25 + 10

Add the numbers:

25 + 10 = 35

7 x^{5} = 35

Divide both sides by

7

x^{5} = 5

For

x^{n} = f (a)

, n is odd, the solution is

3 x^{3} + 8 x^{2} - 3 = 0

x (x - 3)^{2} - 4 (x - 3)^{3} = 0

(x + 5)^{3} = - 27

x^{3} - 24 x = 5 x^{2}

36 k^{3} + 48 k^{2} - 84 k - 112 = 0

What are the solutions to the equation 5^2+10=7x^5 ?
The solutions to the equation 5^2+10=7x^5 are x=\sqrt[5]{5}
Find the zeros of 5^2+10=7x^5
The zeros of 5^2+10=7x^5 are x=\sqrt[5]{5}