What are the solutions to the equation x(x-3)^2-4(x-3)^3=0 ?

The solutions to the equation x(x-3)^2-4(x-3)^3=0 are x=3,x=4

Find the zeros of x(x-3)^2-4(x-3)^3=0

The zeros of x(x-3)^2-4(x-3)^3=0 are x=3,x=4

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x (x - 3)^{2} - 4 (x - 3)^{3} = 0

x = 3, x = 4

Solution steps

x (x - 3)^{2} - 4 (x - 3)^{3} = 0

Factor

x (x - 3)^{2} - 4 (x - 3)^{3} : - 3 (x - 3)^{2} (x - 4)

- 3 (x - 3)^{2} (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x - 4 = 0

Solve

x - 3 = 0 : x = 3

Solve

x - 4 = 0 : x = 4

The solutions are

x = 3, x = 4

(x + 5)^{3} = - 27

x^{3} - 24 x = 5 x^{2}

36 k^{3} + 48 k^{2} - 84 k - 112 = 0

r^{3} + 12 r^{2} - 60 r + 64 = 0

x, y^{4} = C x^{3} + 2

What are the solutions to the equation x(x-3)^2-4(x-3)^3=0 ?
The solutions to the equation x(x-3)^2-4(x-3)^3=0 are x=3,x=4
Find the zeros of x(x-3)^2-4(x-3)^3=0
The zeros of x(x-3)^2-4(x-3)^3=0 are x=3,x=4