What are the solutions to the equation 36k^3+48k^2-84k-112=0 ?

The solutions to the equation 36k^3+48k^2-84k-112=0 are k=-4/3 ,k=-sqrt(7/3),k=sqrt(7/3)

Find the zeros of 36k^3+48k^2-84k-112=0

The zeros of 36k^3+48k^2-84k-112=0 are k=-4/3 ,k=-sqrt(7/3),k=sqrt(7/3)

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36 k^{3} + 48 k^{2} - 84 k - 112 = 0

k = - \frac{4}{3}, k = - \frac{7}{3}, k = \frac{7}{3}

Decimal Notation

k = - 1.33333 \dots, k = - 1.52752 \dots, k = 1.52752 \dots

Solution steps

36 k^{3} + 48 k^{2} - 84 k - 112 = 0

Factor

36 k^{3} + 48 k^{2} - 84 k - 112 : 4 (3 k + 4) (3 k + 7) (3 k - 7)

4 (3 k + 4) (3 k + 7) (3 k - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 k + 4 = 0 or 3 k + 7 = 0 or 3 k - 7 = 0

Solve

3 k + 4 = 0 : k = - \frac{4}{3}

Solve

3 k + 7 = 0 : k = - \frac{7}{3}

Solve

3 k - 7 = 0 : k = \frac{7}{3}

The solutions are

k = - \frac{4}{3}, k = - \frac{7}{3}, k = \frac{7}{3}

r^{3} + 12 r^{2} - 60 r + 64 = 0

x, y^{4} = C x^{3} + 2

- 2 x^{4} + 7 = 3 x + 4

y^{4} - 7 y^{2} + 6 y^{1} = 0

9 x^{3} - 63 x^{2} - 16 x + 112 = 0

What are the solutions to the equation 36k^3+48k^2-84k-112=0 ?
The solutions to the equation 36k^3+48k^2-84k-112=0 are k=-4/3 ,k=-sqrt(7/3),k=sqrt(7/3)
Find the zeros of 36k^3+48k^2-84k-112=0
The zeros of 36k^3+48k^2-84k-112=0 are k=-4/3 ,k=-sqrt(7/3),k=sqrt(7/3)