What are the solutions to the equation r^3+12r^2-60r+64=0 ?

The solutions to the equation r^3+12r^2-60r+64=0 are r=2,r=-16

Find the zeros of r^3+12r^2-60r+64=0

The zeros of r^3+12r^2-60r+64=0 are r=2,r=-16

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r^{3} + 12 r^{2} - 60 r + 64 = 0

r = 2, r = - 16

Solution steps

r^{3} + 12 r^{2} - 60 r + 64 = 0

Factor

r^{3} + 12 r^{2} - 60 r + 64 : (r - 2)^{2} (r + 16)

(r - 2)^{2} (r + 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r - 2 = 0 or r + 16 = 0

Solve

r - 2 = 0 : r = 2

Solve

r + 16 = 0 : r = - 16

The solutions are

r = 2, r = - 16

x, y^{4} = C x^{3} + 2

- 2 x^{4} + 7 = 3 x + 4

y^{4} - 7 y^{2} + 6 y^{1} = 0

9 x^{3} - 63 x^{2} - 16 x + 112 = 0

y^{4} - 6 y^{2} + 8 = 0

What are the solutions to the equation r^3+12r^2-60r+64=0 ?
The solutions to the equation r^3+12r^2-60r+64=0 are r=2,r=-16
Find the zeros of r^3+12r^2-60r+64=0
The zeros of r^3+12r^2-60r+64=0 are r=2,r=-16