What are the solutions to the equation 9x^3-63x^2-16x+112=0 ?

The solutions to the equation 9x^3-63x^2-16x+112=0 are x=7,x=-4/3 ,x= 4/3

Find the zeros of 9x^3-63x^2-16x+112=0

The zeros of 9x^3-63x^2-16x+112=0 are x=7,x=-4/3 ,x= 4/3

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9 x^{3} - 63 x^{2} - 16 x + 112 = 0

x = 7, x = - \frac{4}{3}, x = \frac{4}{3}

Solution steps

9 x^{3} - 63 x^{2} - 16 x + 112 = 0

Factor

9 x^{3} - 63 x^{2} - 16 x + 112 : (x - 7) (3 x + 4) (3 x - 4)

(x - 7) (3 x + 4) (3 x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 7 = 0 or 3 x + 4 = 0 or 3 x - 4 = 0

Solve

x - 7 = 0 : x = 7

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

Solve

3 x - 4 = 0 : x = \frac{4}{3}

The solutions are

x = 7, x = - \frac{4}{3}, x = \frac{4}{3}

y^{4} - 6 y^{2} + 8 = 0

20000 = 5000 (1 + \frac{x}{2})^{20}

- x^{3} + 2 x^{2} - x - 2 = 0

x^{4} - 12 x^{2} + 20 = 0

x^{3} - 4 x^{2} + 8 = 0

What are the solutions to the equation 9x^3-63x^2-16x+112=0 ?
The solutions to the equation 9x^3-63x^2-16x+112=0 are x=7,x=-4/3 ,x= 4/3
Find the zeros of 9x^3-63x^2-16x+112=0
The zeros of 9x^3-63x^2-16x+112=0 are x=7,x=-4/3 ,x= 4/3