What are the solutions to the equation 3(x+9)(x^2-81)=0 ?

The solutions to the equation 3(x+9)(x^2-81)=0 are x=-9,x=9

Find the zeros of 3(x+9)(x^2-81)=0

The zeros of 3(x+9)(x^2-81)=0 are x=-9,x=9

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3 (x + 9) (x^{2} - 81) = 0

x = - 9, x = 9

Solution steps

3 (x + 9) (x^{2} - 81) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 9 = 0 or x^{2} - 81 = 0

Solve

x + 9 = 0 : x = - 9

Solve

x^{2} - 81 = 0 : x = 9, x = - 9

The solutions are

x = - 9, x = 9

x^{3} - 9 x^{2} + 24 x - 16 = 0

2 x^{3} = (x - 1)^{3}

16 x = 2 x^{4}

- 3 x (2 x - 5) (x^{2} + 25) = 0

3 x^{2} = x^{4}

What are the solutions to the equation 3(x+9)(x^2-81)=0 ?
The solutions to the equation 3(x+9)(x^2-81)=0 are x=-9,x=9
Find the zeros of 3(x+9)(x^2-81)=0
The zeros of 3(x+9)(x^2-81)=0 are x=-9,x=9