What are the solutions to the equation 2=(1+x)^{12} ?

The solutions to the equation 2=(1+x)^{12} are x=\sqrt[12]{2}-1,x=-\sqrt[12]{2}-1

Find the zeros of 2=(1+x)^{12}

The zeros of 2=(1+x)^{12} are x=\sqrt[12]{2}-1,x=-\sqrt[12]{2}-1

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2 = (1 + x)^{12}

Decimal Notation

x = 0.05946 \dots, x = - 2.05946 \dots

Solution steps

2 = (1 + x)^{12}

Switch sides

(1 + x)^{12} = 2

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x (x^{2} - 9) = 4 (9 - x^{2})

x^{4} - x^{3} + 3 x^{2} - 9 x - 54 = 0

x^{3} + 3 x^{2} + 4 x + 2 = 0

2 x^{3} + 5 x^{2} + 32 x + 80 = 0

0 = x^{4}

What are the solutions to the equation 2=(1+x)^{12} ?
The solutions to the equation 2=(1+x)^{12} are x=\sqrt[12]{2}-1,x=-\sqrt[12]{2}-1
Find the zeros of 2=(1+x)^{12}
The zeros of 2=(1+x)^{12} are x=\sqrt[12]{2}-1,x=-\sqrt[12]{2}-1