What are the solutions to the equation 27x^3+27x^2+9x+1=0 ?

The solutions to the equation 27x^3+27x^2+9x+1=0 are x=-1/3

Find the zeros of 27x^3+27x^2+9x+1=0

The zeros of 27x^3+27x^2+9x+1=0 are x=-1/3

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27 x^{3} + 27 x^{2} + 9 x + 1 = 0

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

27 x^{3} + 27 x^{2} + 9 x + 1 = 0

Factor

27 x^{3} + 27 x^{2} + 9 x + 1 : (3 x + 1)^{3}

(3 x + 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 1 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

The solution is

x = - \frac{1}{3}

4 x^{17} = 68

- x^{3} + x^{2} + 6 x = 0

(81 x^{2} - 100) (x^{2} - 14) = 0

6 x + 21 x^{2} + 12 x^{3} = 0

2 x^{5} - 4 x - 7 = 0

What are the solutions to the equation 27x^3+27x^2+9x+1=0 ?
The solutions to the equation 27x^3+27x^2+9x+1=0 are x=-1/3
Find the zeros of 27x^3+27x^2+9x+1=0
The zeros of 27x^3+27x^2+9x+1=0 are x=-1/3