What are the solutions to the equation 2x^2-17x+8=0 ?

The solutions to the equation 2x^2-17x+8=0 are x=8,x= 1/2

Find the zeros of 2x^2-17x+8=0

The zeros of 2x^2-17x+8=0 are x=8,x= 1/2

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2 x^{2} - 17 x + 8 = 0

x = 8, x = \frac{1}{2}

Decimal Notation

x = 8, x = 0.5

Solution steps

2 x^{2} - 17 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

(- 17)^{2} - 4 \cdot 2 \cdot 8 = 15

x_{1, 2} = \frac{- ( - 17 ) \pm 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 15}{2 \cdot 2}, x_{2} = \frac{- ( - 17 ) - 15}{2 \cdot 2}

x = \frac{- ( - 17 ) + 15}{2 \cdot 2} : 8

x = \frac{- ( - 17 ) - 15}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 8, x = \frac{1}{2}

112 = 4 + 96 t - 16 t^{2}

2 \cdot π \cdot 7

6 z - 7 > 8 z + 2

c^{2} - 10 c + 24

9 x^{2} - 12 x = 0

What are the solutions to the equation 2x^2-17x+8=0 ?
The solutions to the equation 2x^2-17x+8=0 are x=8,x= 1/2
Find the zeros of 2x^2-17x+8=0
The zeros of 2x^2-17x+8=0 are x=8,x= 1/2