What are the solutions to the equation 21y^4=(B)(7y^3) ?

The solutions to the equation 21y^4=(B)(7y^3) are y=0,y= B/3

Find the zeros of 21y^4=(B)(7y^3)

The zeros of 21y^4=(B)(7y^3) are y=0,y= B/3

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21 y^{4} = (B) (7 y^{3})

y = 0, y = \frac{B}{3}

Solution steps

21 y^{4} = (B) (7 y^{3})

Move

(B) (7 y^{3})

to the left side

21 y^{4} - B \cdot 7 y^{3} = 0

Factor

21 y^{4} - B \cdot 7 y^{3} : 7 y^{3} (3 y - B)

7 y^{3} (3 y - B) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 3 y - B = 0

Solve

3 y - B = 0 : y = \frac{B}{3}

The solutions are

y = 0, y = \frac{B}{3}

x, y^{2} = C x^{3} + 3

x^{4} + 2 x^{3} - 24 x^{2} = 0

27 - x^{3} = 0

400 = \frac{4}{3} π r^{3}

3 x^{4} + x^{2} - 4 = 0

What are the solutions to the equation 21y^4=(B)(7y^3) ?
The solutions to the equation 21y^4=(B)(7y^3) are y=0,y= B/3
Find the zeros of 21y^4=(B)(7y^3)
The zeros of 21y^4=(B)(7y^3) are y=0,y= B/3