What are the solutions to the equation x^4-4x^3-6x^2+4x+5=0 ?

The solutions to the equation x^4-4x^3-6x^2+4x+5=0 are x=-1,x=5,x=1

Find the zeros of x^4-4x^3-6x^2+4x+5=0

The zeros of x^4-4x^3-6x^2+4x+5=0 are x=-1,x=5,x=1

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x^{4} - 4 x^{3} - 6 x^{2} + 4 x + 5 = 0

x = - 1, x = 5, x = 1

Solution steps

x^{4} - 4 x^{3} - 6 x^{2} + 4 x + 5 = 0

Factor

x^{4} - 4 x^{3} - 6 x^{2} + 4 x + 5 : (x + 1)^{2} (x - 5) (x - 1)

(x + 1)^{2} (x - 5) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 5 = 0 or x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 5 = 0 : x = 5

Solve

x - 1 = 0 : x = 1

The solutions are

x = - 1, x = 5, x = 1

x 0.12 x^{2} + 40 x - 32 = 0

1.035 = (1 + \frac{r}{4})^{4}

- x^{3} - x + 2 = 0

x^{4} - 3 x^{3} + 3 x^{2} + 1 = 0

2 x^{4} - 12 x^{2} + 16 = 0

What are the solutions to the equation x^4-4x^3-6x^2+4x+5=0 ?
The solutions to the equation x^4-4x^3-6x^2+4x+5=0 are x=-1,x=5,x=1
Find the zeros of x^4-4x^3-6x^2+4x+5=0
The zeros of x^4-4x^3-6x^2+4x+5=0 are x=-1,x=5,x=1