What are the solutions to the equation x^4-5x+6=0 ?

The solutions to the equation x^4-5x+6=0 are No Solution for x\in\mathbb{R}

Find the zeros of x^4-5x+6=0

The zeros of x^4-5x+6=0 are No Solution for x\in\mathbb{R}

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x^{4} - 5 x + 6 = 0

No Solution for x \in R

Solution steps

x^{4} - 5 x + 6 = 0

Find one solution for

x^{4} - 5 x + 6 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

(2 x^{2} - 1)^{2} = 36

(3 y + 18) (y^{2} - 11 y + 30) = 0

y, x^{2} + y^{3} = c

2 x^{3} + 13 x^{2} + 16 x + 5 = 0

r^{4} - 2 r^{2} + 1 = 0

What are the solutions to the equation x^4-5x+6=0 ?
The solutions to the equation x^4-5x+6=0 are No Solution for x\in\mathbb{R}
Find the zeros of x^4-5x+6=0
The zeros of x^4-5x+6=0 are No Solution for x\in\mathbb{R}