What are the solutions to the equation 3x^3+5x^2+4x-1=0 ?

The solutions to the equation 3x^3+5x^2+4x-1=0 are x\approx 0.19621…

Find the zeros of 3x^3+5x^2+4x-1=0

The zeros of 3x^3+5x^2+4x-1=0 are x\approx 0.19621…

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3 x^{3} + 5 x^{2} + 4 x - 1 = 0

x \approx 0.19621 \dots

Solution steps

3 x^{3} + 5 x^{2} + 4 x - 1 = 0

Find one solution for

3 x^{3} + 5 x^{2} + 4 x - 1 = 0

using Newton-Raphson:

x \approx 0.19621 \dots

Apply long division:

\frac{3 x ^{3} + 5 x ^{2} + 4 x - 1}{x - 0.19621 \dots} = 3 x^{2} + 5.58863 \dots x + 5.09655 \dots

3 x^{2} + 5.58863 \dots x + 5.09655 \dots \approx 0

Find one solution for

3 x^{2} + 5.58863 \dots x + 5.09655 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 0.19621 \dots

2 x^{3} - 3 x^{2} - 8 x - 3 = 0

v^{3} - 2 v^{2} - 16 v = - 32

r^{4} - 2 r^{3} + 10 r^{2} - 18 r + 9 = 0

0 = x^{3} + 2 x^{2} - 4 x - 8

x, y + 3 = x^{3}

What are the solutions to the equation 3x^3+5x^2+4x-1=0 ?
The solutions to the equation 3x^3+5x^2+4x-1=0 are x\approx 0.19621…
Find the zeros of 3x^3+5x^2+4x-1=0
The zeros of 3x^3+5x^2+4x-1=0 are x\approx 0.19621…