What are the solutions to the equation 12x^3-84x^2+120x=0 ?

The solutions to the equation 12x^3-84x^2+120x=0 are x=0,x=2,x=5

Find the zeros of 12x^3-84x^2+120x=0

The zeros of 12x^3-84x^2+120x=0 are x=0,x=2,x=5

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12 x^{3} - 84 x^{2} + 120 x = 0

x = 0, x = 2, x = 5

Solution steps

12 x^{3} - 84 x^{2} + 120 x = 0

Factor

12 x^{3} - 84 x^{2} + 120 x : 12 x (x - 2) (x - 5)

12 x (x - 2) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x - 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 5 = 0 : x = 5

The solutions are

x = 0, x = 2, x = 5

- x^{3} + 12 x^{2} - 29 x + 18 = 0

715 = 5 x^{3}

4 x^{4} - x + 1 = 0

2 x (4 x^{4}) = (2 x^{5}) x^{4}

x^{3} - 16 x^{2} + 60 x = 0

What are the solutions to the equation 12x^3-84x^2+120x=0 ?
The solutions to the equation 12x^3-84x^2+120x=0 are x=0,x=2,x=5
Find the zeros of 12x^3-84x^2+120x=0
The zeros of 12x^3-84x^2+120x=0 are x=0,x=2,x=5