What are the solutions to the equation 0=x^3-2x^2-x+2 ?

The solutions to the equation 0=x^3-2x^2-x+2 are x=2,x=-1,x=1

Find the zeros of 0=x^3-2x^2-x+2

The zeros of 0=x^3-2x^2-x+2 are x=2,x=-1,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{3} - 2 x^{2} - x + 2

x = 2, x = - 1, x = 1

Solution steps

0 = x^{3} - 2 x^{2} - x + 2

Switch sides

x^{3} - 2 x^{2} - x + 2 = 0

Factor

x^{3} - 2 x^{2} - x + 2 : (x - 2) (x + 1) (x - 1)

(x - 2) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 2, x = - 1, x = 1

x^{3} + x^{2} - 7 x + 15 = 0

a x^{3} - 2 x^{2} - 3 x = 0

x^{2} (x - 1) (x + 2) = 0

x^{3} - 2 x^{2} - 4 x + 3 = 0

x^{3} + x^{2} + 16 x + 16 = 0

What are the solutions to the equation 0=x^3-2x^2-x+2 ?
The solutions to the equation 0=x^3-2x^2-x+2 are x=2,x=-1,x=1
Find the zeros of 0=x^3-2x^2-x+2
The zeros of 0=x^3-2x^2-x+2 are x=2,x=-1,x=1