What are the solutions to the equation 0=2x^3-x^2-3x ?

The solutions to the equation 0=2x^3-x^2-3x are x=0,x=-1,x= 3/2

Find the zeros of 0=2x^3-x^2-3x

The zeros of 0=2x^3-x^2-3x are x=0,x=-1,x= 3/2

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0 = 2 x^{3} - x^{2} - 3 x

x = 0, x = - 1, x = \frac{3}{2}

Solution steps

0 = 2 x^{3} - x^{2} - 3 x

Switch sides

2 x^{3} - x^{2} - 3 x = 0

Factor

2 x^{3} - x^{2} - 3 x : x (x + 1) (2 x - 3)

x (x + 1) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or 2 x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = 0, x = - 1, x = \frac{3}{2}

3 (x^{2} - 14) (x^{2} + 36) = 0

n^{3} = 10

4 x^{3} + 3 x^{2} - 6 x + 4 = 0

x^{4} - 36 x^{2} = - 35

x^{4} - 6 x^{3} + 5 x^{2} = 0

What are the solutions to the equation 0=2x^3-x^2-3x ?
The solutions to the equation 0=2x^3-x^2-3x are x=0,x=-1,x= 3/2
Find the zeros of 0=2x^3-x^2-3x
The zeros of 0=2x^3-x^2-3x are x=0,x=-1,x= 3/2