What are the solutions to the equation 3(x^2-14)(x^2+36)=0 ?

The solutions to the equation 3(x^2-14)(x^2+36)=0 are x=6i,x=-6i,x=-sqrt(14),x=sqrt(14)

Find the zeros of 3(x^2-14)(x^2+36)=0

The zeros of 3(x^2-14)(x^2+36)=0 are x=6i,x=-6i,x=-sqrt(14),x=sqrt(14)

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3 (x^{2} - 14) (x^{2} + 36) = 0

x = 6 i, x = - 6 i, x = - 14, x = 14

Solution steps

3 (x^{2} - 14) (x^{2} + 36) = 0

Factor

3 (x^{2} - 14) (x^{2} + 36) : 3 (x^{2} + 36) (x + 14) (x - 14)

3 (x^{2} + 36) (x + 14) (x - 14) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} + 36 = 0 or x + 14 = 0 or x - 14 = 0

Solve

x^{2} + 36 = 0 : x = 6 i, x = - 6 i

Solve

x + 14 = 0 : x = - 14

Solve

x - 14 = 0 : x = 14

The solutions are

x = 6 i, x = - 6 i, x = - 14, x = 14

n^{3} = 10

4 x^{3} + 3 x^{2} - 6 x + 4 = 0

x^{4} - 36 x^{2} = - 35

x^{4} - 6 x^{3} + 5 x^{2} = 0

3 x^{4} + 24 x = 0

What are the solutions to the equation 3(x^2-14)(x^2+36)=0 ?
The solutions to the equation 3(x^2-14)(x^2+36)=0 are x=6i,x=-6i,x=-sqrt(14),x=sqrt(14)
Find the zeros of 3(x^2-14)(x^2+36)=0
The zeros of 3(x^2-14)(x^2+36)=0 are x=6i,x=-6i,x=-sqrt(14),x=sqrt(14)