What are the solutions to the equation -4x^5+32x^3+192x=0 ?

The solutions to the equation -4x^5+32x^3+192x=0 are x=0,x=2i,x=-2i,x=-2sqrt(3),x=2sqrt(3)

Find the zeros of -4x^5+32x^3+192x=0

The zeros of -4x^5+32x^3+192x=0 are x=0,x=2i,x=-2i,x=-2sqrt(3),x=2sqrt(3)

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- 4 x^{5} + 32 x^{3} + 192 x = 0

x = 0, x = 2 i, x = - 2 i, x = - 23, x = 23

Solution steps

- 4 x^{5} + 32 x^{3} + 192 x = 0

Factor

- 4 x^{5} + 32 x^{3} + 192 x : - 4 x (x^{2} + 4) (x + 23) (x - 23)

- 4 x (x^{2} + 4) (x + 23) (x - 23) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 4 = 0 or x + 23 = 0 or x - 23 = 0

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

Solve

x + 23 = 0 : x = - 23

Solve

x - 23 = 0 : x = 23

The solutions are

x = 0, x = 2 i, x = - 2 i, x = - 23, x = 23

- 2 x^{3} - x^{2} + 8 x - 5 = 0

(x^{3}) (x + 3) = 5

0 = 12 x^{3} - 12 x^{2}

y^{3} + 5 y^{2} - 49 y - 245 = 0

x^{3} + 6 x^{2} - 9 x + 4 = 0

What are the solutions to the equation -4x^5+32x^3+192x=0 ?
The solutions to the equation -4x^5+32x^3+192x=0 are x=0,x=2i,x=-2i,x=-2sqrt(3),x=2sqrt(3)
Find the zeros of -4x^5+32x^3+192x=0
The zeros of -4x^5+32x^3+192x=0 are x=0,x=2i,x=-2i,x=-2sqrt(3),x=2sqrt(3)