What are the solutions to the equation x^3-8x+7=0 ?

The solutions to the equation x^3-8x+7=0 are x=1,x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2

Find the zeros of x^3-8x+7=0

The zeros of x^3-8x+7=0 are x=1,x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2

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x^{3} - 8 x + 7 = 0

x = 1, x = \frac{- 1 + 29}{2}, x = \frac{- 1 - 29}{2}

Solution steps

x^{3} - 8 x + 7 = 0

Factor

x^{3} - 8 x + 7 : (x - 1) (x^{2} + x - 7)

(x - 1) (x^{2} + x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} + x - 7 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} + x - 7 = 0 : x = \frac{- 1 + 29}{2}, x = \frac{- 1 - 29}{2}

The solutions are

x = 1, x = \frac{- 1 + 29}{2}, x = \frac{- 1 - 29}{2}

b^{3} = 216

2 + x^{3} - 5 x^{2} = 0

(w - 3)^{2} (w + 1)^{2} = 0

5 = \frac{4}{3} π x^{3}

x^{8} + x^{5} + x^{2} - x + 1 = 0

What are the solutions to the equation x^3-8x+7=0 ?
The solutions to the equation x^3-8x+7=0 are x=1,x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2
Find the zeros of x^3-8x+7=0
The zeros of x^3-8x+7=0 are x=1,x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2