What are the solutions to the equation b^3=216 ?

The solutions to the equation b^3=216 are b=6,b=-3+3sqrt(3)i,b=-3-3sqrt(3)i

Find the zeros of b^3=216

The zeros of b^3=216 are b=6,b=-3+3sqrt(3)i,b=-3-3sqrt(3)i

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b^{3} = 216

b = 6, b = - 3 + 33 i, b = - 3 - 33 i

Solution steps

b^{3} = 216

For

x^{3} = f (a)

the solutions are

Simplify

b = 6, b = - 3 + 33 i, b = - 3 - 33 i

2 + x^{3} - 5 x^{2} = 0

(w - 3)^{2} (w + 1)^{2} = 0

5 = \frac{4}{3} π x^{3}

x^{8} + x^{5} + x^{2} - x + 1 = 0

8 x (x^{2} - 1)^{3} = 0

What are the solutions to the equation b^3=216 ?
The solutions to the equation b^3=216 are b=6,b=-3+3sqrt(3)i,b=-3-3sqrt(3)i
Find the zeros of b^3=216
The zeros of b^3=216 are b=6,b=-3+3sqrt(3)i,b=-3-3sqrt(3)i