What are the solutions to the equation x^3-7x-4=0 ?

The solutions to the equation x^3-7x-4=0 are x\approx-0.60270…,x\approx-2.29240…,x\approx 2.89510…

Find the zeros of x^3-7x-4=0

The zeros of x^3-7x-4=0 are x\approx-0.60270…,x\approx-2.29240…,x\approx 2.89510…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 7 x - 4 = 0

x \approx - 0.60270 \dots, x \approx - 2.29240 \dots, x \approx 2.89510 \dots

Solution steps

x^{3} - 7 x - 4 = 0

Find one solution for

x^{3} - 7 x - 4 = 0

using Newton-Raphson:

x \approx - 0.60270 \dots

Apply long division:

\frac{x ^{3} - 7 x - 4}{x + 0.60270 \dots} = x^{2} - 0.60270 \dots x - 6.63674 \dots

x^{2} - 0.60270 \dots x - 6.63674 \dots \approx 0

Find one solution for

x^{2} - 0.60270 \dots x - 6.63674 \dots = 0

using Newton-Raphson:

x \approx - 2.29240 \dots

Apply long division:

\frac{x ^{2} - 0.60270 \dots x - 6.63674 \dots}{x + 2.29240 \dots} = x - 2.89510 \dots

x - 2.89510 \dots \approx 0

x \approx 2.89510 \dots

The solutions are

x \approx - 0.60270 \dots, x \approx - 2.29240 \dots, x \approx 2.89510 \dots

- a^{3} - 2 a^{2} + 4 a + 8 = 0

x^{3} - 7 x - 3 = 0

a, y = 9 a^{4} - a^{2} b^{2}

r, f = - 1 r^{8}

1 - 4 x^{2} - 4 x^{4} = 0

What are the solutions to the equation x^3-7x-4=0 ?
The solutions to the equation x^3-7x-4=0 are x\approx-0.60270…,x\approx-2.29240…,x\approx 2.89510…
Find the zeros of x^3-7x-4=0
The zeros of x^3-7x-4=0 are x\approx-0.60270…,x\approx-2.29240…,x\approx 2.89510…