What are the solutions to the equation 2x^3-x^2-7x-3=0 ?

The solutions to the equation 2x^3-x^2-7x-3=0 are x=-1/2 ,x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2

Find the zeros of 2x^3-x^2-7x-3=0

The zeros of 2x^3-x^2-7x-3=0 are x=-1/2 ,x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{3} - x^{2} - 7 x - 3 = 0

x = - \frac{1}{2}, x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

Decimal Notation

x = - 0.5, x = 2.30277 \dots, x = - 1.30277 \dots

Solution steps

2 x^{3} - x^{2} - 7 x - 3 = 0

Factor

2 x^{3} - x^{2} - 7 x - 3 : (2 x + 1) (x^{2} - x - 3)

(2 x + 1) (x^{2} - x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or x^{2} - x - 3 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x^{2} - x - 3 = 0 : x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

The solutions are

x = - \frac{1}{2}, x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

5 x^{3} - 3 x + 1 = 0

x^{3} + 10 x^{2} - 1625 + 18750 = 0

2 x^{3} - 4 x = 0

z, z^{3} = 1

u^{3} + u^{2} + 1 = 0

What are the solutions to the equation 2x^3-x^2-7x-3=0 ?
The solutions to the equation 2x^3-x^2-7x-3=0 are x=-1/2 ,x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2
Find the zeros of 2x^3-x^2-7x-3=0
The zeros of 2x^3-x^2-7x-3=0 are x=-1/2 ,x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2