What are the solutions to the equation x^3=512x ?

The solutions to the equation x^3=512x are x=0,x=-16sqrt(2),x=16sqrt(2)

Find the zeros of x^3=512x

The zeros of x^3=512x are x=0,x=-16sqrt(2),x=16sqrt(2)

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x^{3} = 512 x

x = 0, x = - 162, x = 162

Decimal Notation

x = 0, x = - 22.62741 \dots, x = 22.62741 \dots

Solution steps

x^{3} = 512 x

Move

512 x

to the left side

x^{3} - 512 x = 0

Factor

x^{3} - 512 x : x (x + 162) (x - 162)

x (x + 162) (x - 162) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 162 = 0 or x - 162 = 0

Solve

x + 162 = 0 : x = - 162

Solve

x - 162 = 0 : x = 162

The solutions are

x = 0, x = - 162, x = 162

x, f = 2 x^{(3)} + 8 f (- 6)

(6 x - 1) (x^{2} + 1) = 0

48 = 3 r^{4}

x, 8 x^{3} + 4 y = 32

x^{3} + 8 = \frac{9 x ^{3}}{2}

What are the solutions to the equation x^3=512x ?
The solutions to the equation x^3=512x are x=0,x=-16sqrt(2),x=16sqrt(2)
Find the zeros of x^3=512x
The zeros of x^3=512x are x=0,x=-16sqrt(2),x=16sqrt(2)