What are the solutions to the equation (x+1)^3=27 ?

The solutions to the equation (x+1)^3=27 are x=2,x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2

Find the zeros of (x+1)^3=27

The zeros of (x+1)^3=27 are x=2,x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2

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(x + 1)^{3} = 27

x = 2, x = - \frac{5}{2} + i \frac{3 3}{2}, x = - \frac{5}{2} - i \frac{3 3}{2}

Solution steps

(x + 1)^{3} = 27

For

g^{3} (x) = f (a)

the solutions are

Solve

The solutions are

x = 2, x = - \frac{5}{2} + i \frac{3 3}{2}, x = - \frac{5}{2} - i \frac{3 3}{2}

x^{3} - 6 x^{2} + 9 x - 1 = 0

2 x^{4} = 128

333 = 80 \cdot (1 + x)^{7}

- a^{3} + 24 a^{2} - 180 a + 432 = 0

x^{4} = 6 x^{2}

What are the solutions to the equation (x+1)^3=27 ?
The solutions to the equation (x+1)^3=27 are x=2,x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2
Find the zeros of (x+1)^3=27
The zeros of (x+1)^3=27 are x=2,x=-5/2+i(3sqrt(3))/2 ,x=-5/2-i(3sqrt(3))/2