What are the solutions to the equation 6x^4+8x^2=26x^3 ?

The solutions to the equation 6x^4+8x^2=26x^3 are x=0,x= 1/3 ,x=4

Find the zeros of 6x^4+8x^2=26x^3

The zeros of 6x^4+8x^2=26x^3 are x=0,x= 1/3 ,x=4

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6 x^{4} + 8 x^{2} = 26 x^{3}

x = 0, x = \frac{1}{3}, x = 4

Decimal Notation

x = 0, x = 0.33333 \dots, x = 4

Solution steps

6 x^{4} + 8 x^{2} = 26 x^{3}

Move

26 x^{3}

to the left side

6 x^{4} + 8 x^{2} - 26 x^{3} = 0

Factor

6 x^{4} + 8 x^{2} - 26 x^{3} : 2 x^{2} (3 x - 1) (x - 4)

2 x^{2} (3 x - 1) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x - 1 = 0 or x - 4 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x - 4 = 0 : x = 4

The solutions are

x = 0, x = \frac{1}{3}, x = 4

x^{3} - 8 x^{2} + 217 x + 224 = 0

\frac{12 + x}{2} = (x^{2} + 36)^{2}

2 x^{3} + x^{2} - 18 x - 9 = 0

r, S = 30 - r^{30}

(x^{2} - 3 x) (2 x + 3) (x - 1) = 0

What are the solutions to the equation 6x^4+8x^2=26x^3 ?
The solutions to the equation 6x^4+8x^2=26x^3 are x=0,x= 1/3 ,x=4
Find the zeros of 6x^4+8x^2=26x^3
The zeros of 6x^4+8x^2=26x^3 are x=0,x= 1/3 ,x=4