What are the solutions to the equation 2x^5+82x^4+80x^3=0 ?

The solutions to the equation 2x^5+82x^4+80x^3=0 are x=0,x=-1,x=-40

Find the zeros of 2x^5+82x^4+80x^3=0

The zeros of 2x^5+82x^4+80x^3=0 are x=0,x=-1,x=-40

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2 x^{5} + 82 x^{4} + 80 x^{3} = 0

x = 0, x = - 1, x = - 40

Solution steps

2 x^{5} + 82 x^{4} + 80 x^{3} = 0

Factor

2 x^{5} + 82 x^{4} + 80 x^{3} : 2 x^{3} (x + 1) (x + 40)

2 x^{3} (x + 1) (x + 40) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x + 40 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 40 = 0 : x = - 40

The solutions are

x = 0, x = - 1, x = - 40

x^{3} - 3 x^{2} + 7 x - 21 = 0

r^{3} + 1 = 0

x^{5} = 32 i

- 2 x^{3} - 2 x^{2} + 1 = 0

12500 = 10000 (1 + X)^{10}

What are the solutions to the equation 2x^5+82x^4+80x^3=0 ?
The solutions to the equation 2x^5+82x^4+80x^3=0 are x=0,x=-1,x=-40
Find the zeros of 2x^5+82x^4+80x^3=0
The zeros of 2x^5+82x^4+80x^3=0 are x=0,x=-1,x=-40