What are the solutions to the equation x^2+2x+5x+10=0 ?

The solutions to the equation x^2+2x+5x+10=0 are x=-2,x=-5

Find the zeros of x^2+2x+5x+10=0

The zeros of x^2+2x+5x+10=0 are x=-2,x=-5

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x^{2} + 2 x + 5 x + 10 = 0

x = - 2, x = - 5

Solution steps

x^{2} + 2 x + 5 x + 10 = 0

Refine

x^{2} + 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 \cdot 1}, x_{2} = \frac{- 7 - 3}{2 \cdot 1}

x = \frac{- 7 + 3}{2 \cdot 1} : - 2

x = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

\frac{g}{2} \leq 2

2 x - 22 > 0.8

a x - b x + b - a - b y + a y

64 - a^{4} b^{4}

v^{2} + 5 v + 4 = 0

What are the solutions to the equation x^2+2x+5x+10=0 ?
The solutions to the equation x^2+2x+5x+10=0 are x=-2,x=-5
Find the zeros of x^2+2x+5x+10=0
The zeros of x^2+2x+5x+10=0 are x=-2,x=-5