What are the solutions to the equation (1+x+x^2)^2=0 ?

The solutions to the equation (1+x+x^2)^2=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

Find the zeros of (1+x+x^2)^2=0

The zeros of (1+x+x^2)^2=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

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(1 + x + x^{2})^{2} = 0

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

Solution steps

(1 + x + x^{2})^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

1 + x + x^{2} = 0 : x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

The solutions are

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

3 = (1 + x)^{12}

a = \frac{1}{2} x^{5} x^{8}

k^{3} - 3 k^{2} - 16 k + 48 = 0

3 x^{3} + 7 x^{2} = 6 x

y^{4} - 37 y^{2} = - 36

What are the solutions to the equation (1+x+x^2)^2=0 ?
The solutions to the equation (1+x+x^2)^2=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2
Find the zeros of (1+x+x^2)^2=0
The zeros of (1+x+x^2)^2=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2