What are the solutions to the equation (s-1)^2(s-3)^2=0 ?

The solutions to the equation (s-1)^2(s-3)^2=0 are s=1,s=3

Find the zeros of (s-1)^2(s-3)^2=0

The zeros of (s-1)^2(s-3)^2=0 are s=1,s=3

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(s - 1)^{2} (s - 3)^{2} = 0

s = 1, s = 3

Solution steps

(s - 1)^{2} (s - 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

s - 1 = 0 or s - 3 = 0

Solve

s - 1 = 0 : s = 1

Solve

s - 3 = 0 : s = 3

The solutions are

s = 1, s = 3

140 π = 2 π r^{10}

- 4 x^{3} + 6 x = 0

4 x^{3} + x^{2} - 4 x - 1 = 0

(1 + x)^{12} = 10968

- 2 x^{2} + x^{3} + 1 = 0

What are the solutions to the equation (s-1)^2(s-3)^2=0 ?
The solutions to the equation (s-1)^2(s-3)^2=0 are s=1,s=3
Find the zeros of (s-1)^2(s-3)^2=0
The zeros of (s-1)^2(s-3)^2=0 are s=1,s=3