What are the solutions to the equation 140pi=2pir^{10} ?

The solutions to the equation 140pi=2pir^{10} are r=-\sqrt[10]{70},r=\sqrt[10]{70}

Find the zeros of 140pi=2pir^{10}

The zeros of 140pi=2pir^{10} are r=-\sqrt[10]{70},r=\sqrt[10]{70}

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140 π = 2 π r^{10}

Decimal Notation

r = - 1.52936 \dots, r = 1.52936 \dots

Solution steps

140 π = 2 π r^{10}

Move

2 π r^{10}

to the left side

140 π - 2 π r^{10} = 0

Factor

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

No Solution for

r \in R

Solve

No Solution for

r \in R

The solutions are

- 4 x^{3} + 6 x = 0

4 x^{3} + x^{2} - 4 x - 1 = 0

(1 + x)^{12} = 10968

- 2 x^{2} + x^{3} + 1 = 0

19.6 y^{3} - 40.57 y^{2} + 25 = 0

What are the solutions to the equation 140pi=2pir^{10} ?
The solutions to the equation 140pi=2pir^{10} are r=-\sqrt[10]{70},r=\sqrt[10]{70}
Find the zeros of 140pi=2pir^{10}
The zeros of 140pi=2pir^{10} are r=-\sqrt[10]{70},r=\sqrt[10]{70}