What are the solutions to the equation -4x^3+6x=0 ?

The solutions to the equation -4x^3+6x=0 are x=0,x=-sqrt(3/2),x=sqrt(3/2)

Find the zeros of -4x^3+6x=0

The zeros of -4x^3+6x=0 are x=0,x=-sqrt(3/2),x=sqrt(3/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{3} + 6 x = 0

x = 0, x = - \frac{3}{2}, x = \frac{3}{2}

Decimal Notation

x = 0, x = - 1.22474 \dots, x = 1.22474 \dots

Solution steps

- 4 x^{3} + 6 x = 0

Factor

- 4 x^{3} + 6 x : - 2 x (2 x + 3) (2 x - 3)

- 2 x (2 x + 3) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 3 = 0 or 2 x - 3 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = 0, x = - \frac{3}{2}, x = \frac{3}{2}

4 x^{3} + x^{2} - 4 x - 1 = 0

(1 + x)^{12} = 10968

- 2 x^{2} + x^{3} + 1 = 0

19.6 y^{3} - 40.57 y^{2} + 25 = 0

(8 x^{7}) + (8 x^{4}) = 8 x (x)

What are the solutions to the equation -4x^3+6x=0 ?
The solutions to the equation -4x^3+6x=0 are x=0,x=-sqrt(3/2),x=sqrt(3/2)
Find the zeros of -4x^3+6x=0
The zeros of -4x^3+6x=0 are x=0,x=-sqrt(3/2),x=sqrt(3/2)