What are the solutions to the equation 133=137(1+r)^{10} ?

The solutions to the equation 133=137(1+r)^{10} are r=\sqrt[10]{133/137}-1,r=-\sqrt[10]{133/137}-1

Find the zeros of 133=137(1+r)^{10}

The zeros of 133=137(1+r)^{10} are r=\sqrt[10]{133/137}-1,r=-\sqrt[10]{133/137}-1

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133 = 137 (1 + r)^{10}

Decimal Notation

r = - 0.00295 \dots, r = - 1.99704 \dots

Solution steps

133 = 137 (1 + r)^{10}

Switch sides

137 (1 + r)^{10} = 133

Divide both sides by

137

(1 + r)^{10} = \frac{133}{137}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

- x^{4} + 27 x^{2} - 10 x = 0

- 2 x^{4} + 7 = 2 x - 3

2 x^{5} - 12 x^{3} = 0

3 x^{5} + 18 x^{4} - 21 x^{3} = 0

- 4 r^{5} + 4 r^{4} + 0.25 r - 0.25 = 0

What are the solutions to the equation 133=137(1+r)^{10} ?
The solutions to the equation 133=137(1+r)^{10} are r=\sqrt[10]{133/137}-1,r=-\sqrt[10]{133/137}-1
Find the zeros of 133=137(1+r)^{10}
The zeros of 133=137(1+r)^{10} are r=\sqrt[10]{133/137}-1,r=-\sqrt[10]{133/137}-1