What are the solutions to the equation -x^4+27x^2-10x=0 ?

The solutions to the equation -x^4+27x^2-10x=0 are x=0,x=5,x=(-5+sqrt(33))/2 ,x=(-5-sqrt(33))/2

Find the zeros of -x^4+27x^2-10x=0

The zeros of -x^4+27x^2-10x=0 are x=0,x=5,x=(-5+sqrt(33))/2 ,x=(-5-sqrt(33))/2

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- x^{4} + 27 x^{2} - 10 x = 0

x = 0, x = 5, x = \frac{- 5 + 33}{2}, x = \frac{- 5 - 33}{2}

Decimal Notation

x = 0, x = 5, x = 0.37228 \dots, x = - 5.37228 \dots

Solution steps

- x^{4} + 27 x^{2} - 10 x = 0

Factor

- x^{4} + 27 x^{2} - 10 x : - x (x - 5) (x^{2} + 5 x - 2)

- x (x - 5) (x^{2} + 5 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 5 = 0 or x^{2} + 5 x - 2 = 0

Solve

x - 5 = 0 : x = 5

Solve

x^{2} + 5 x - 2 = 0 : x = \frac{- 5 + 33}{2}, x = \frac{- 5 - 33}{2}

The solutions are

x = 0, x = 5, x = \frac{- 5 + 33}{2}, x = \frac{- 5 - 33}{2}

- 2 x^{4} + 7 = 2 x - 3

2 x^{5} - 12 x^{3} = 0

3 x^{5} + 18 x^{4} - 21 x^{3} = 0

- 4 r^{5} + 4 r^{4} + 0.25 r - 0.25 = 0

x^{8} + 36 = x - 3 + 25

What are the solutions to the equation -x^4+27x^2-10x=0 ?
The solutions to the equation -x^4+27x^2-10x=0 are x=0,x=5,x=(-5+sqrt(33))/2 ,x=(-5-sqrt(33))/2
Find the zeros of -x^4+27x^2-10x=0
The zeros of -x^4+27x^2-10x=0 are x=0,x=5,x=(-5+sqrt(33))/2 ,x=(-5-sqrt(33))/2