What are the solutions to the equation 2x^3-7x^2+13x=0 ?

The solutions to the equation 2x^3-7x^2+13x=0 are x=0,x= 7/4+i(sqrt(55))/4 ,x= 7/4-i(sqrt(55))/4

Find the zeros of 2x^3-7x^2+13x=0

The zeros of 2x^3-7x^2+13x=0 are x=0,x= 7/4+i(sqrt(55))/4 ,x= 7/4-i(sqrt(55))/4

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2 x^{3} - 7 x^{2} + 13 x = 0

x = 0, x = \frac{7}{4} + i \frac{55}{4}, x = \frac{7}{4} - i \frac{55}{4}

Solution steps

2 x^{3} - 7 x^{2} + 13 x = 0

Factor

2 x^{3} - 7 x^{2} + 13 x : x (2 x^{2} - 7 x + 13)

x (2 x^{2} - 7 x + 13) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x^{2} - 7 x + 13 = 0

Solve

2 x^{2} - 7 x + 13 = 0 : x = \frac{7}{4} + i \frac{55}{4}, x = \frac{7}{4} - i \frac{55}{4}

The solutions are

x = 0, x = \frac{7}{4} + i \frac{55}{4}, x = \frac{7}{4} - i \frac{55}{4}

x (x^{2} - 8 x + 4) = 0

x^{4} - 6 x^{2} - 7 x - 6 = 0

x^{4} - 8 x^{3} + 21 x^{2} - 20 x + 5 = 0

b^{3} - 125 = 0

4 x^{3} - 8 x^{2} + 5 x - 73 = 0

What are the solutions to the equation 2x^3-7x^2+13x=0 ?
The solutions to the equation 2x^3-7x^2+13x=0 are x=0,x= 7/4+i(sqrt(55))/4 ,x= 7/4-i(sqrt(55))/4
Find the zeros of 2x^3-7x^2+13x=0
The zeros of 2x^3-7x^2+13x=0 are x=0,x= 7/4+i(sqrt(55))/4 ,x= 7/4-i(sqrt(55))/4