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2x^3+72=20018x^5+6x^4-24x^3=6x^22y^4+3y^3-16y^2+15y-4=0(u+4)^3=-(u+4)^2solvefor R,V= 4/3 piR^3solve for
Frequently Asked Questions (FAQ)
What are the solutions to the equation k^3=343 ?
The solutions to the equation k^3=343 are k=7,k=-7/2+(7sqrt(3))/2 i,k=-7/2-(7sqrt(3))/2 iFind the zeros of k^3=343
The zeros of k^3=343 are k=7,k=-7/2+(7sqrt(3))/2 i,k=-7/2-(7sqrt(3))/2 i