What are the solutions to the equation 2.5x^3+1.56^2-3x+1.5=0 ?

The solutions to the equation 2.5x^3+1.56^2-3x+1.5=0 are x\approx-1.49971…

Find the zeros of 2.5x^3+1.56^2-3x+1.5=0

The zeros of 2.5x^3+1.56^2-3x+1.5=0 are x\approx-1.49971…

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2.5 x^{3} + 1.5 6^{2} - 3 x + 1.5 = 0

x \approx - 1.49971 \dots

Solution steps

2.5 x^{3} + 1.5 6^{2} - 3 x + 1.5 = 0

Expand

2.5 x^{3} + 1.5 6^{2} - 3 x + 1.5 : 2.5 x^{3} - 3 x + 3.9336

2.5 x^{3} - 3 x + 3.9336 = 0

Find one solution for

2.5 x^{3} - 3 x + 3.9336 = 0

using Newton-Raphson:

x \approx - 1.49971 \dots

Apply long division:

\frac{2.5 x ^{3} - 3 x + 3.9336}{x + 1.49971 \dots} = 2.5 x^{2} - 3.74929 \dots x + 2.62289 \dots

2.5 x^{2} - 3.74929 \dots x + 2.62289 \dots \approx 0

Find one solution for

2.5 x^{2} - 3.74929 \dots x + 2.62289 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 1.49971 \dots

\frac{2 p ^{3}}{2} = 54

(y^{2} - y - 30) (5 y - 40) = 0

x^{3} + x^{2} + 4 x - 4 = 0

144 x^{4} + 24 x^{2} + 1 = 0

77 = 16 \cdot (1 + r)^{4}

What are the solutions to the equation 2.5x^3+1.56^2-3x+1.5=0 ?
The solutions to the equation 2.5x^3+1.56^2-3x+1.5=0 are x\approx-1.49971…
Find the zeros of 2.5x^3+1.56^2-3x+1.5=0
The zeros of 2.5x^3+1.56^2-3x+1.5=0 are x\approx-1.49971…