What are the solutions to the equation -7x-8+x^4=0 ?

The solutions to the equation -7x-8+x^4=0 are x=-1,x\approx 2.19928…

Find the zeros of -7x-8+x^4=0

The zeros of -7x-8+x^4=0 are x=-1,x\approx 2.19928…

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- 7 x - 8 + x^{4} = 0

x = - 1, x \approx 2.19928 \dots

Solution steps

- 7 x - 8 + x^{4} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{4} - 7 x - 8 = 0

Factor

x^{4} - 7 x - 8 : (x + 1) (x^{3} - x^{2} + x - 8)

(x + 1) (x^{3} - x^{2} + x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{3} - x^{2} + x - 8 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{3} - x^{2} + x - 8 = 0 : x \approx 2.19928 \dots

The solutions are

x = - 1, x \approx 2.19928 \dots

9 x^{3} + 9 = 0

x^{3} + 5 x^{2} + 2 x - 8 = x^{2} + 3 x - 4

(3 w - 21) (w^{2} + 9 w + 20) = 0

y, 34 x - y^{3} = 23 x - 9

0 = x^{3} + x + 1

What are the solutions to the equation -7x-8+x^4=0 ?
The solutions to the equation -7x-8+x^4=0 are x=-1,x\approx 2.19928…
Find the zeros of -7x-8+x^4=0
The zeros of -7x-8+x^4=0 are x=-1,x\approx 2.19928…