What are the solutions to the equation b^7-49b^5=0 ?

The solutions to the equation b^7-49b^5=0 are b=0,b=-7,b=7

Find the zeros of b^7-49b^5=0

The zeros of b^7-49b^5=0 are b=0,b=-7,b=7

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b^{7} - 49 b^{5} = 0

b = 0, b = - 7, b = 7

Solution steps

b^{7} - 49 b^{5} = 0

Factor

b^{7} - 49 b^{5} : b^{5} (b + 7) (b - 7)

b^{5} (b + 7) (b - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

b = 0 or b + 7 = 0 or b - 7 = 0

Solve

b + 7 = 0 : b = - 7

Solve

b - 7 = 0 : b = 7

The solutions are

b = 0, b = - 7, b = 7

3 c^{3} + 6 c^{2} - 105 c = 0

x, x^{4} - y^{4} = 343

3 x^{3} = 5 x^{2} + 2 x

x^{6} = \frac{1}{729}

73 = 12 \cdot (1 + R)^{3}

What are the solutions to the equation b^7-49b^5=0 ?
The solutions to the equation b^7-49b^5=0 are b=0,b=-7,b=7
Find the zeros of b^7-49b^5=0
The zeros of b^7-49b^5=0 are b=0,b=-7,b=7