What are the solutions to the equation 3x^3=5x^2+2x ?

The solutions to the equation 3x^3=5x^2+2x are x=0,x=-1/3 ,x=2

Find the zeros of 3x^3=5x^2+2x

The zeros of 3x^3=5x^2+2x are x=0,x=-1/3 ,x=2

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3 x^{3} = 5 x^{2} + 2 x

x = 0, x = - \frac{1}{3}, x = 2

Solution steps

3 x^{3} = 5 x^{2} + 2 x

Move

2 x

to the left side

3 x^{3} - 2 x = 5 x^{2}

Move

5 x^{2}

to the left side

3 x^{3} - 2 x - 5 x^{2} = 0

Factor

3 x^{3} - 2 x - 5 x^{2} : x (3 x + 1) (x - 2)

x (3 x + 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 1 = 0 or x - 2 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - \frac{1}{3}, x = 2

x^{6} = \frac{1}{729}

73 = 12 \cdot (1 + R)^{3}

- 2 x (x + 1) (x^{2} + 49) = 0

x, y^{2} = (x + 4)^{3}

(4 x^{4}) + 5 = (4 - 4)

What are the solutions to the equation 3x^3=5x^2+2x ?
The solutions to the equation 3x^3=5x^2+2x are x=0,x=-1/3 ,x=2
Find the zeros of 3x^3=5x^2+2x
The zeros of 3x^3=5x^2+2x are x=0,x=-1/3 ,x=2