What are the solutions to the equation 3c^3+6c^2-105c=0 ?

The solutions to the equation 3c^3+6c^2-105c=0 are c=0,c=5,c=-7

Find the zeros of 3c^3+6c^2-105c=0

The zeros of 3c^3+6c^2-105c=0 are c=0,c=5,c=-7

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3 c^{3} + 6 c^{2} - 105 c = 0

c = 0, c = 5, c = - 7

Solution steps

3 c^{3} + 6 c^{2} - 105 c = 0

Factor

3 c^{3} + 6 c^{2} - 105 c : 3 c (c - 5) (c + 7)

3 c (c - 5) (c + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

c = 0 or c - 5 = 0 or c + 7 = 0

Solve

c - 5 = 0 : c = 5

Solve

c + 7 = 0 : c = - 7

The solutions are

c = 0, c = 5, c = - 7

x, x^{4} - y^{4} = 343

3 x^{3} = 5 x^{2} + 2 x

x^{6} = \frac{1}{729}

73 = 12 \cdot (1 + R)^{3}

- 2 x (x + 1) (x^{2} + 49) = 0

What are the solutions to the equation 3c^3+6c^2-105c=0 ?
The solutions to the equation 3c^3+6c^2-105c=0 are c=0,c=5,c=-7
Find the zeros of 3c^3+6c^2-105c=0
The zeros of 3c^3+6c^2-105c=0 are c=0,c=5,c=-7