What are the solutions to the equation x^4+12x^3+44x^2+48x=3465 ?

The solutions to the equation x^4+12x^3+44x^2+48x=3465 are x=5,x=-11,x=-3+3sqrt(6)i,x=-3-3sqrt(6)i

Find the zeros of x^4+12x^3+44x^2+48x=3465

The zeros of x^4+12x^3+44x^2+48x=3465 are x=5,x=-11,x=-3+3sqrt(6)i,x=-3-3sqrt(6)i

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x^{4} + 12 x^{3} + 44 x^{2} + 48 x = 3465

x = 5, x = - 11, x = - 3 + 36 i, x = - 3 - 36 i

Solution steps

x^{4} + 12 x^{3} + 44 x^{2} + 48 x = 3465

Move

3465

to the left side

x^{4} + 12 x^{3} + 44 x^{2} + 48 x - 3465 = 0

Factor

x^{4} + 12 x^{3} + 44 x^{2} + 48 x - 3465 : (x - 5) (x + 11) (x^{2} + 6 x + 63)

(x - 5) (x + 11) (x^{2} + 6 x + 63) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x + 11 = 0 or x^{2} + 6 x + 63 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 11 = 0 : x = - 11

Solve

x^{2} + 6 x + 63 = 0 : x = - 3 + 36 i, x = - 3 - 36 i

The solutions are

x = 5, x = - 11, x = - 3 + 36 i, x = - 3 - 36 i

x^{2} 16 x + 64 = 0

127 + 5 x + 3 + 10 x^{7} + 88 = 360

x^{3} - 3 x^{2} - 28 x + 60 = 0

35 = \frac{x ^{2} ( 4 x + 6 )}{2}

22 = 3 (x + 3)^{3} - 2

What are the solutions to the equation x^4+12x^3+44x^2+48x=3465 ?
The solutions to the equation x^4+12x^3+44x^2+48x=3465 are x=5,x=-11,x=-3+3sqrt(6)i,x=-3-3sqrt(6)i
Find the zeros of x^4+12x^3+44x^2+48x=3465
The zeros of x^4+12x^3+44x^2+48x=3465 are x=5,x=-11,x=-3+3sqrt(6)i,x=-3-3sqrt(6)i